Base | Representation |
---|---|
bin | 11001011111110110… |
… | …10111101111101001 |
3 | 1022100000020222122011 |
4 | 30233323113233221 |
5 | 211013340313133 |
6 | 10142202355521 |
7 | 663140351545 |
oct | 145773275751 |
9 | 38300228564 |
10 | 13688994793 |
11 | 5895098441 |
12 | 27a04bbba1 |
13 | 13a2059b26 |
14 | 93c07aa25 |
15 | 551b9d6cd |
hex | 32fed7be9 |
13688994793 has 2 divisors, whose sum is σ = 13688994794. Its totient is φ = 13688994792.
The previous prime is 13688994763. The next prime is 13688994841. The reversal of 13688994793 is 39749988631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10034429584 + 3654565209 = 100172^2 + 60453^2 .
It is a cyclic number.
It is not a de Polignac number, because 13688994793 - 221 = 13686897641 is a prime.
It is a super-2 number, since 2×136889947932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13688994713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6844497396 + 6844497397.
It is an arithmetic number, because the mean of its divisors is an integer number (6844497397).
Almost surely, 213688994793 is an apocalyptic number.
It is an amenable number.
13688994793 is a deficient number, since it is larger than the sum of its proper divisors (1).
13688994793 is an equidigital number, since it uses as much as digits as its factorization.
13688994793 is an evil number, because the sum of its binary digits is even.
The product of its digits is 70543872, while the sum is 67.
The spelling of 13688994793 in words is "thirteen billion, six hundred eighty-eight million, nine hundred ninety-four thousand, seven hundred ninety-three".
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