Search a number
-
+
13689433 is a prime number
BaseRepresentation
bin110100001110…
…001001011001
3221202111101001
4310032021121
512001030213
61205225001
7224233612
oct64161131
927674331
1013689433
11780008a
124702161
132ab3c74
141b64c09
1513061dd
hexd0e259

13689433 has 2 divisors, whose sum is σ = 13689434. Its totient is φ = 13689432.

The previous prime is 13689397. The next prime is 13689461. The reversal of 13689433 is 33498631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10478169 + 3211264 = 3237^2 + 1792^2 .

It is a cyclic number.

It is not a de Polignac number, because 13689433 - 217 = 13558361 is a prime.

It is a super-2 number, since 2×136894332 = 374801151722978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13689392 and 13689401.

It is not a weakly prime, because it can be changed into another prime (13689133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6844716 + 6844717.

It is an arithmetic number, because the mean of its divisors is an integer number (6844717).

Almost surely, 213689433 is an apocalyptic number.

It is an amenable number.

13689433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13689433 is an equidigital number, since it uses as much as digits as its factorization.

13689433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 46656, while the sum is 37.

The square root of 13689433 is about 3699.9233775850. The cubic root of 13689433 is about 239.2187151887.

It can be divided in two parts, 1368 and 9433, that added together give a palindrome (10801).

The spelling of 13689433 in words is "thirteen million, six hundred eighty-nine thousand, four hundred thirty-three".