Base | Representation |
---|---|
bin | 111111110010001100… |
… | …0001001101011100011 |
3 | 111002120001121111122011 |
4 | 1333210120021223203 |
5 | 4221011213210111 |
6 | 142531540453351 |
7 | 12616244505511 |
oct | 1774430115343 |
9 | 432501544564 |
10 | 136975522531 |
11 | 53100125491 |
12 | 226689aa257 |
13 | cbbc0ba363 |
14 | 68b5a934b1 |
15 | 386a445021 |
hex | 1fe4609ae3 |
136975522531 has 2 divisors, whose sum is σ = 136975522532. Its totient is φ = 136975522530.
The previous prime is 136975522459. The next prime is 136975522601. The reversal of 136975522531 is 135225579631.
It is a strong prime.
It is an emirp because it is prime and its reverse (135225579631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136975522531 is a prime.
It is a super-2 number, since 2×1369755225312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (136975522231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68487761265 + 68487761266.
It is an arithmetic number, because the mean of its divisors is an integer number (68487761266).
Almost surely, 2136975522531 is an apocalyptic number.
136975522531 is a deficient number, since it is larger than the sum of its proper divisors (1).
136975522531 is an equidigital number, since it uses as much as digits as its factorization.
136975522531 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1701000, while the sum is 49.
The spelling of 136975522531 in words is "one hundred thirty-six billion, nine hundred seventy-five million, five hundred twenty-two thousand, five hundred thirty-one".
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