1369774853 has 4 divisors (see below), whose sum is σ = 1369855968. Its totient is φ = 1369693740.

The previous prime is 1369774837. The next prime is 1369774873. The reversal of 1369774853 is 3584779631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3584779631 = 449 ⋅7983919.

It is a cyclic number.

It is not a de Polignac number, because 1369774853 - 2⁴ = 1369774837 is a prime.

It is a super-2 number, since 2×1369774853² = 3752566295822343218, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1369774795 and 1369774804.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1369774873) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4601 + ... + 52542.

It is an arithmetic number, because the mean of its divisors is an integer number (342463992).

Almost surely, 2^1369774853 is an apocalyptic number.

It is an amenable number.

1369774853 is a deficient number, since it is larger than the sum of its proper divisors (81115).

1369774853 is an equidigital number, since it uses as much as digits as its factorization.

1369774853 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81114.

The product of its digits is 3810240, while the sum is 53.

The square root of 1369774853 is about 37010.4695052630. The cubic root of 1369774853 is about 1110.5796969303.

The spelling of 1369774853 in words is "one billion, three hundred sixty-nine million, seven hundred seventy-four thousand, eight hundred fifty-three".