Base | Representation |
---|---|
bin | 11111001001100111110100… |
… | …110010001000011010101001 |
3 | 122222002010200211220212202011 |
4 | 133021213310302020122221 |
5 | 120424104342211413024 |
6 | 1203213124244435521 |
7 | 40566654350160244 |
oct | 3711476462103251 |
9 | 588063624825664 |
10 | 137000678622889 |
11 | 3a71a730533a34 |
12 | 134477960a8ba1 |
13 | 5b5a154676a03 |
14 | 25b8c225a625b |
15 | 10c8a7e646094 |
hex | 7c99f4c886a9 |
137000678622889 has 2 divisors, whose sum is σ = 137000678622890. Its totient is φ = 137000678622888.
The previous prime is 137000678622827. The next prime is 137000678622943. The reversal of 137000678622889 is 988226876000731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 136906848518400 + 93830104489 = 11700720^2 + 306317^2 .
It is a cyclic number.
It is not a de Polignac number, because 137000678622889 - 27 = 137000678622761 is a prime.
It is not a weakly prime, because it can be changed into another prime (137000678622289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68500339311444 + 68500339311445.
It is an arithmetic number, because the mean of its divisors is an integer number (68500339311445).
Almost surely, 2137000678622889 is an apocalyptic number.
It is an amenable number.
137000678622889 is a deficient number, since it is larger than the sum of its proper divisors (1).
137000678622889 is an equidigital number, since it uses as much as digits as its factorization.
137000678622889 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97542144, while the sum is 67.
The spelling of 137000678622889 in words is "one hundred thirty-seven trillion, six hundred seventy-eight million, six hundred twenty-two thousand, eight hundred eighty-nine".
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