Base | Representation |
---|---|
bin | 10011111011111011110… |
… | …110111010010101000001 |
3 | 11211222021101212212221201 |
4 | 103323323312322111001 |
5 | 134421302404413113 |
6 | 2525214132021201 |
7 | 200660333001115 |
oct | 23737366722501 |
9 | 4758241785851 |
10 | 1370025076033 |
11 | 48902a491259 |
12 | 1a162a761801 |
13 | 9c2677b1783 |
14 | 4a44964b745 |
15 | 2598683acdd |
hex | 13efbdba541 |
1370025076033 has 2 divisors, whose sum is σ = 1370025076034. Its totient is φ = 1370025076032.
The previous prime is 1370025076003. The next prime is 1370025076081. The reversal of 1370025076033 is 3306705200731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 924564940849 + 445460135184 = 961543^2 + 667428^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1370025076033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1370025075983 and 1370025076001.
It is not a weakly prime, because it can be changed into another prime (1370025076003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685012538016 + 685012538017.
It is an arithmetic number, because the mean of its divisors is an integer number (685012538017).
Almost surely, 21370025076033 is an apocalyptic number.
It is an amenable number.
1370025076033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1370025076033 is an equidigital number, since it uses as much as digits as its factorization.
1370025076033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 79380, while the sum is 37.
The spelling of 1370025076033 in words is "one trillion, three hundred seventy billion, twenty-five million, seventy-six thousand, thirty-three".
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