Base | Representation |
---|---|
bin | 111111110011111100… |
… | …1110100100000011011 |
3 | 111002201011221000220101 |
4 | 1333213321310200123 |
5 | 4221121334232342 |
6 | 142541452440231 |
7 | 12620563364335 |
oct | 1774771644033 |
9 | 432634830811 |
10 | 137034680347 |
11 | 53130560644 |
12 | 22684779077 |
13 | cbcb430b96 |
14 | 68bd892455 |
15 | 387072d3b7 |
hex | 1fe7e7481b |
137034680347 has 2 divisors, whose sum is σ = 137034680348. Its totient is φ = 137034680346.
The previous prime is 137034680291. The next prime is 137034680399. The reversal of 137034680347 is 743086430731.
It is a strong prime.
It is an emirp because it is prime and its reverse (743086430731) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 137034680347 - 215 = 137034647579 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 137034680297 and 137034680306.
It is not a weakly prime, because it can be changed into another prime (137034680147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68517340173 + 68517340174.
It is an arithmetic number, because the mean of its divisors is an integer number (68517340174).
Almost surely, 2137034680347 is an apocalyptic number.
137034680347 is a deficient number, since it is larger than the sum of its proper divisors (1).
137034680347 is an equidigital number, since it uses as much as digits as its factorization.
137034680347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1016064, while the sum is 46.
The spelling of 137034680347 in words is "one hundred thirty-seven billion, thirty-four million, six hundred eighty thousand, three hundred forty-seven".
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