Base | Representation |
---|---|
bin | 10011111100011010100… |
… | …100000011110000111011 |
3 | 11212000121022020022002222 |
4 | 103330122210003300323 |
5 | 134423331244241033 |
6 | 2525341213314255 |
7 | 201006156501626 |
oct | 23743244036073 |
9 | 4760538208088 |
10 | 1370540227643 |
11 | 489274257294 |
12 | 1a175319598b |
13 | 9c31a440202 |
14 | 4a497c28dbd |
15 | 259b6b98598 |
hex | 13f1a903c3b |
1370540227643 has 2 divisors, whose sum is σ = 1370540227644. Its totient is φ = 1370540227642.
The previous prime is 1370540227619. The next prime is 1370540227669. The reversal of 1370540227643 is 3467220450731.
It is a weak prime.
It is an emirp because it is prime and its reverse (3467220450731) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1370540227643 - 224 = 1370523450427 is a prime.
It is a super-2 number, since 2×13705402276432 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1370540227594 and 1370540227603.
It is not a weakly prime, because it can be changed into another prime (1370540227603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685270113821 + 685270113822.
It is an arithmetic number, because the mean of its divisors is an integer number (685270113822).
Almost surely, 21370540227643 is an apocalyptic number.
1370540227643 is a deficient number, since it is larger than the sum of its proper divisors (1).
1370540227643 is an equidigital number, since it uses as much as digits as its factorization.
1370540227643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 846720, while the sum is 44.
The spelling of 1370540227643 in words is "one trillion, three hundred seventy billion, five hundred forty million, two hundred twenty-seven thousand, six hundred forty-three".
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