Base | Representation |
---|---|
bin | 10011111100011011100… |
… | …011011001000111000011 |
3 | 11212000122110110210110112 |
4 | 103330123203121013003 |
5 | 134423400022031042 |
6 | 2525343005221535 |
7 | 201006450560501 |
oct | 23743343310703 |
9 | 4760573423415 |
10 | 1370556830147 |
11 | 489282666a6a |
12 | 1a17588618ab |
13 | 9c320a0408b |
14 | 4a49a10b671 |
15 | 259b8377982 |
hex | 13f1b8d91c3 |
1370556830147 has 2 divisors, whose sum is σ = 1370556830148. Its totient is φ = 1370556830146.
The previous prime is 1370556830143. The next prime is 1370556830189. The reversal of 1370556830147 is 7410386550731.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1370556830147 - 22 = 1370556830143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1370556830095 and 1370556830104.
It is not a weakly prime, because it can be changed into another prime (1370556830141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685278415073 + 685278415074.
It is an arithmetic number, because the mean of its divisors is an integer number (685278415074).
Almost surely, 21370556830147 is an apocalyptic number.
1370556830147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1370556830147 is an equidigital number, since it uses as much as digits as its factorization.
1370556830147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2116800, while the sum is 50.
The spelling of 1370556830147 in words is "one trillion, three hundred seventy billion, five hundred fifty-six million, eight hundred thirty thousand, one hundred forty-seven".
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