Base | Representation |
---|---|
bin | 11001100001110101… |
… | …11010000100000001 |
3 | 1022101011121011212201 |
4 | 30300322322010001 |
5 | 211032121303213 |
6 | 10143555353201 |
7 | 663432051346 |
oct | 146072720401 |
9 | 38334534781 |
10 | 13705650433 |
11 | 58a3534032 |
12 | 27a5bb2801 |
13 | 13a563bc37 |
14 | 9403747cd |
15 | 55338d6dd |
hex | 330eba101 |
13705650433 has 2 divisors, whose sum is σ = 13705650434. Its totient is φ = 13705650432.
The previous prime is 13705650377. The next prime is 13705650457. The reversal of 13705650433 is 33405650731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9410552064 + 4295098369 = 97008^2 + 65537^2 .
It is a cyclic number.
It is not a de Polignac number, because 13705650433 - 29 = 13705649921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13705650392 and 13705650401.
It is not a weakly prime, because it can be changed into another prime (13705650493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6852825216 + 6852825217.
It is an arithmetic number, because the mean of its divisors is an integer number (6852825217).
Almost surely, 213705650433 is an apocalyptic number.
It is an amenable number.
13705650433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13705650433 is an equidigital number, since it uses as much as digits as its factorization.
13705650433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 37.
It can be divided in two parts, 137056 and 50433, that added together give a square (187489 = 4332).
The spelling of 13705650433 in words is "thirteen billion, seven hundred five million, six hundred fifty thousand, four hundred thirty-three".
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