Base | Representation |
---|---|
bin | 111111110111001100… |
… | …0100111111011001001 |
3 | 111002222202112111200221 |
4 | 1333232120213323021 |
5 | 4221332203343234 |
6 | 143000335230041 |
7 | 12623353552363 |
oct | 1775630477311 |
9 | 432882474627 |
10 | 137143418569 |
11 | 53186980243 |
12 | 226b5078321 |
13 | cc17b13b21 |
14 | 68d00b9d33 |
15 | 387a05beb4 |
hex | 1fee627ec9 |
137143418569 has 2 divisors, whose sum is σ = 137143418570. Its totient is φ = 137143418568.
The previous prime is 137143418551. The next prime is 137143418593. The reversal of 137143418569 is 965814341731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 104192092944 + 32951325625 = 322788^2 + 181525^2 .
It is a cyclic number.
It is not a de Polignac number, because 137143418569 - 25 = 137143418537 is a prime.
It is a super-2 number, since 2×1371434185692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (137143418509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68571709284 + 68571709285.
It is an arithmetic number, because the mean of its divisors is an integer number (68571709285).
Almost surely, 2137143418569 is an apocalyptic number.
It is an amenable number.
137143418569 is a deficient number, since it is larger than the sum of its proper divisors (1).
137143418569 is an equidigital number, since it uses as much as digits as its factorization.
137143418569 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2177280, while the sum is 52.
The spelling of 137143418569 in words is "one hundred thirty-seven billion, one hundred forty-three million, four hundred eighteen thousand, five hundred sixty-nine".
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