Base | Representation |
---|---|
bin | 1100011110010100011001… |
… | …1111100010100100011011 |
3 | 1210120010211212002000100001 |
4 | 3013211012133202210123 |
5 | 3244201321342434212 |
6 | 45100331243553431 |
7 | 2613606546056146 |
oct | 307450637424433 |
9 | 53503755060301 |
10 | 13715013249307 |
11 | 440856047a847 |
12 | 165608a22b877 |
13 | 78642162cc16 |
14 | 355b4b1dd05d |
15 | 18bb5b7be657 |
hex | c79467e291b |
13715013249307 has 2 divisors, whose sum is σ = 13715013249308. Its totient is φ = 13715013249306.
The previous prime is 13715013249283. The next prime is 13715013249319. The reversal of 13715013249307 is 70394231051731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13715013249307 - 215 = 13715013216539 is a prime.
It is not a weakly prime, because it can be changed into another prime (13715013249337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6857506624653 + 6857506624654.
It is an arithmetic number, because the mean of its divisors is an integer number (6857506624654).
Almost surely, 213715013249307 is an apocalyptic number.
13715013249307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13715013249307 is an equidigital number, since it uses as much as digits as its factorization.
13715013249307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 476280, while the sum is 46.
The spelling of 13715013249307 in words is "thirteen trillion, seven hundred fifteen billion, thirteen million, two hundred forty-nine thousand, three hundred seven".
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