Base | Representation |
---|---|
bin | 10011111110101011011… |
… | …000011001111100111001 |
3 | 11212020212122000212122002 |
4 | 103332223120121330321 |
5 | 134443320241302423 |
6 | 2530422245110345 |
7 | 201123321221513 |
oct | 23765330317471 |
9 | 4766778025562 |
10 | 1372969869113 |
11 | 48a300774947 |
12 | 1a21109b83b5 |
13 | 9c61690689b |
14 | 4a6487a2bb3 |
15 | 25aaa127228 |
hex | 13fab619f39 |
1372969869113 has 2 divisors, whose sum is σ = 1372969869114. Its totient is φ = 1372969869112.
The previous prime is 1372969869097. The next prime is 1372969869137. The reversal of 1372969869113 is 3119689692731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 755279188624 + 617690680489 = 869068^2 + 785933^2 .
It is a cyclic number.
It is not a de Polignac number, because 1372969869113 - 24 = 1372969869097 is a prime.
It is a super-2 number, since 2×13729698691132 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1372969869113.
It is not a weakly prime, because it can be changed into another prime (1372969860113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 686484934556 + 686484934557.
It is an arithmetic number, because the mean of its divisors is an integer number (686484934557).
Almost surely, 21372969869113 is an apocalyptic number.
It is an amenable number.
1372969869113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1372969869113 is an equidigital number, since it uses as much as digits as its factorization.
1372969869113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 26453952, while the sum is 65.
The spelling of 1372969869113 in words is "one trillion, three hundred seventy-two billion, nine hundred sixty-nine million, eight hundred sixty-nine thousand, one hundred thirteen".
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