Base | Representation |
---|---|
bin | 10011111111101001011… |
… | …011111111011011011001 |
3 | 11212100120012002121211111 |
4 | 103333221123333123121 |
5 | 140002433303341231 |
6 | 2531113440100321 |
7 | 201161162524246 |
oct | 23775133773331 |
9 | 4770505077744 |
10 | 1374010996441 |
11 | 48a795429256 |
12 | 1a23616046a1 |
13 | 9c751513765 |
14 | 4a706b785cd |
15 | 25b1b72e4b1 |
hex | 13fe96ff6d9 |
1374010996441 has 2 divisors, whose sum is σ = 1374010996442. Its totient is φ = 1374010996440.
The previous prime is 1374010996387. The next prime is 1374010996481. The reversal of 1374010996441 is 1446990104731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 814693980816 + 559317015625 = 902604^2 + 747875^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1374010996441 is a prime.
It is not a weakly prime, because it can be changed into another prime (1374010996481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 687005498220 + 687005498221.
It is an arithmetic number, because the mean of its divisors is an integer number (687005498221).
Almost surely, 21374010996441 is an apocalyptic number.
It is an amenable number.
1374010996441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1374010996441 is an equidigital number, since it uses as much as digits as its factorization.
1374010996441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 653184, while the sum is 49.
The spelling of 1374010996441 in words is "one trillion, three hundred seventy-four billion, ten million, nine hundred ninety-six thousand, four hundred forty-one".
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