Base | Representation |
---|---|
bin | 111111111111111111… |
… | …1111111111110111011 |
3 | 111010202100122020021112 |
4 | 1333333333333332323 |
5 | 4222433333002103 |
6 | 143045533430535 |
7 | 12633602554103 |
oct | 1777777777673 |
9 | 433670566245 |
10 | 137438953403 |
11 | 53318784a04 |
12 | 2277803b44b |
13 | cc6410a3cb |
14 | 691b44a203 |
15 | 3895e87cd8 |
hex | 1fffffffbb |
137438953403 has 2 divisors, whose sum is σ = 137438953404. Its totient is φ = 137438953402.
The previous prime is 137438953349. The next prime is 137438953427. The reversal of 137438953403 is 304359834731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 137438953403 - 210 = 137438952379 is a prime.
It is not a weakly prime, because it can be changed into another prime (137438953903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68719476701 + 68719476702.
It is an arithmetic number, because the mean of its divisors is an integer number (68719476702).
Almost surely, 2137438953403 is an apocalyptic number.
137438953403 is a deficient number, since it is larger than the sum of its proper divisors (1).
137438953403 is an equidigital number, since it uses as much as digits as its factorization.
137438953403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3265920, while the sum is 50.
The spelling of 137438953403 in words is "one hundred thirty-seven billion, four hundred thirty-eight million, nine hundred fifty-three thousand, four hundred three".
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