Base | Representation |
---|---|
bin | 10100000000100111101… |
… | …100010011100010010110 |
3 | 11212110020222102220011121 |
4 | 110000213230103202112 |
5 | 140012103144214002 |
6 | 2531405230354154 |
7 | 201226104365053 |
oct | 24004754234226 |
9 | 4773228386147 |
10 | 1375055460502 |
11 | 490180a61599 |
12 | 1a25b335b95a |
13 | 9c889a1b329 |
14 | 4a7a577c02a |
15 | 25b7d295237 |
hex | 14027b13896 |
1375055460502 has 4 divisors (see below), whose sum is σ = 2062583190756. Its totient is φ = 687527730250.
The previous prime is 1375055460481. The next prime is 1375055460509. The reversal of 1375055460502 is 2050645505731.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×13750554605023 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1375055460509) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 343763865124 + ... + 343763865127.
It is an arithmetic number, because the mean of its divisors is an integer number (515645797689).
Almost surely, 21375055460502 is an apocalyptic number.
1375055460502 is a deficient number, since it is larger than the sum of its proper divisors (687527730254).
1375055460502 is an equidigital number, since it uses as much as digits as its factorization.
1375055460502 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 687527730253.
The product of its (nonzero) digits is 630000, while the sum is 43.
The spelling of 1375055460502 in words is "one trillion, three hundred seventy-five billion, fifty-five million, four hundred sixty thousand, five hundred two".
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