Base | Representation |
---|---|
bin | 10100000000100111110… |
… | …100100100101011001101 |
3 | 11212110021010112000012212 |
4 | 110000213310210223031 |
5 | 140012104223042403 |
6 | 2531405345040205 |
7 | 201226131662630 |
oct | 24004764445315 |
9 | 4773233460185 |
10 | 1375057627853 |
11 | 490182201998 |
12 | 1a25b4026065 |
13 | 9c88a2c99a0 |
14 | 4a7a5b83c17 |
15 | 25b7d5724d8 |
hex | 14027d24acd |
1375057627853 has 48 divisors (see below), whose sum is σ = 1740090352896. Its totient is φ = 1057914224640.
The previous prime is 1375057627849. The next prime is 1375057627861. The reversal of 1375057627853 is 3587267505731.
It is not a de Polignac number, because 1375057627853 - 22 = 1375057627849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1375057627792 and 1375057627801.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1375057627883) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 34410701 + ... + 34450637.
It is an arithmetic number, because the mean of its divisors is an integer number (36251882352).
Almost surely, 21375057627853 is an apocalyptic number.
1375057627853 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1375057627853 is a deficient number, since it is larger than the sum of its proper divisors (365032725043).
1375057627853 is an equidigital number, since it uses as much as digits as its factorization.
1375057627853 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40174 (or 40101 counting only the distinct ones).
The product of its (nonzero) digits is 37044000, while the sum is 59.
The spelling of 1375057627853 in words is "one trillion, three hundred seventy-five billion, fifty-seven million, six hundred twenty-seven thousand, eight hundred fifty-three".
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