Base | Representation |
---|---|
bin | 1100100000011011011101… |
… | …1110001011001011000011 |
3 | 1210200121102112122021221001 |
4 | 3020012313132023023003 |
5 | 3300300044211030412 |
6 | 45125125010512431 |
7 | 2616332152166461 |
oct | 310066736131303 |
9 | 53617375567831 |
10 | 13751268455107 |
11 | 4421975603547 |
12 | 1661107b95717 |
13 | 78997b906b11 |
14 | 3577ca2c9831 |
15 | 18ca7e642957 |
hex | c81b778b2c3 |
13751268455107 has 2 divisors, whose sum is σ = 13751268455108. Its totient is φ = 13751268455106.
The previous prime is 13751268455039. The next prime is 13751268455147. The reversal of 13751268455107 is 70155486215731.
13751268455107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13751268455107 - 211 = 13751268453059 is a prime.
It is not a weakly prime, because it can be changed into another prime (13751268455147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6875634227553 + 6875634227554.
It is an arithmetic number, because the mean of its divisors is an integer number (6875634227554).
Almost surely, 213751268455107 is an apocalyptic number.
13751268455107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13751268455107 is an equidigital number, since it uses as much as digits as its factorization.
13751268455107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7056000, while the sum is 55.
The spelling of 13751268455107 in words is "thirteen trillion, seven hundred fifty-one billion, two hundred sixty-eight million, four hundred fifty-five thousand, one hundred seven".
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