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13753320131 is a prime number
BaseRepresentation
bin11001100111100001…
…10000001011000011
31022111111022001102002
430303300300023003
5211131322221011
610152421214215
7664551202145
oct146360601303
938444261362
1013753320131
115918432a81
1227b9b6136b
1313b248c765
14946822c95
15557657c3b
hex333c302c3

13753320131 has 2 divisors, whose sum is σ = 13753320132. Its totient is φ = 13753320130.

The previous prime is 13753320121. The next prime is 13753320149. The reversal of 13753320131 is 13102335731.

It is a weak prime.

It is an emirp because it is prime and its reverse (13102335731) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13753320131 - 26 = 13753320067 is a prime.

It is a super-2 number, since 2×137533201312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13753320094 and 13753320103.

It is not a weakly prime, because it can be changed into another prime (13753320101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6876660065 + 6876660066.

It is an arithmetic number, because the mean of its divisors is an integer number (6876660066).

Almost surely, 213753320131 is an apocalyptic number.

13753320131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13753320131 is an equidigital number, since it uses as much as digits as its factorization.

13753320131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5670, while the sum is 29.

Adding to 13753320131 its reverse (13102335731), we get a palindrome (26855655862).

The spelling of 13753320131 in words is "thirteen billion, seven hundred fifty-three million, three hundred twenty thousand, one hundred thirty-one".