Base | Representation |
---|---|
bin | 11111010001100000011010… |
… | …110110010111011010000011 |
3 | 200000222221012010201102100012 |
4 | 133101200122312113122003 |
5 | 121011444001141140441 |
6 | 1204310051112015135 |
7 | 40654054644505052 |
oct | 3721403266273203 |
9 | 600887163642305 |
10 | 137542483146371 |
11 | 3a909492013696 |
12 | 135147a33914ab |
13 | 5b9927b68bcc4 |
14 | 25d713d8ca399 |
15 | 10d7be03ae9eb |
hex | 7d181ad97683 |
137542483146371 has 2 divisors, whose sum is σ = 137542483146372. Its totient is φ = 137542483146370.
The previous prime is 137542483146199. The next prime is 137542483146377. The reversal of 137542483146371 is 173641384245731.
It is a strong prime.
It is an emirp because it is prime and its reverse (173641384245731) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 137542483146371 - 218 = 137542482884227 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 137542483146371.
It is not a weakly prime, because it can be changed into another prime (137542483146377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68771241573185 + 68771241573186.
It is an arithmetic number, because the mean of its divisors is an integer number (68771241573186).
Almost surely, 2137542483146371 is an apocalyptic number.
137542483146371 is a deficient number, since it is larger than the sum of its proper divisors (1).
137542483146371 is an equidigital number, since it uses as much as digits as its factorization.
137542483146371 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40642560, while the sum is 59.
The spelling of 137542483146371 in words is "one hundred thirty-seven trillion, five hundred forty-two billion, four hundred eighty-three million, one hundred forty-six thousand, three hundred seventy-one".
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