Base | Representation |
---|---|
bin | 11111010100000000100010… |
… | …001001111110000011011001 |
3 | 200001121100221121220220022211 |
4 | 133110000202021332003121 |
5 | 121022303100012332003 |
6 | 1204521042441315121 |
7 | 41002352215265362 |
oct | 3724004211760331 |
9 | 601540847826284 |
10 | 137714404417753 |
11 | 3a9753950a5449 |
12 | 13541b83495aa1 |
13 | 5bac549686957 |
14 | 26015ac7a6b69 |
15 | 10dc40371a96d |
hex | 7d402227e0d9 |
137714404417753 has 2 divisors, whose sum is σ = 137714404417754. Its totient is φ = 137714404417752.
The previous prime is 137714404417673. The next prime is 137714404417913. The reversal of 137714404417753 is 357714404417731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70256633177929 + 67457771239824 = 8381923^2 + 8213268^2 .
It is a cyclic number.
It is not a de Polignac number, because 137714404417753 - 245 = 102530032328921 is a prime.
It is not a weakly prime, because it can be changed into another prime (137714404117753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68857202208876 + 68857202208877.
It is an arithmetic number, because the mean of its divisors is an integer number (68857202208877).
Almost surely, 2137714404417753 is an apocalyptic number.
It is an amenable number.
137714404417753 is a deficient number, since it is larger than the sum of its proper divisors (1).
137714404417753 is an equidigital number, since it uses as much as digits as its factorization.
137714404417753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27659520, while the sum is 58.
The spelling of 137714404417753 in words is "one hundred thirty-seven trillion, seven hundred fourteen billion, four hundred four million, four hundred seventeen thousand, seven hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.123 sec. • engine limits •