Base | Representation |
---|---|
bin | 10100000010101110110… |
… | …110011110101111110011 |
3 | 11212200010000022110221121 |
4 | 110002232312132233303 |
5 | 140031224200131034 |
6 | 2532422233003111 |
7 | 201336230530045 |
oct | 24025666365763 |
9 | 4780100273847 |
10 | 1377323052019 |
11 | 491134a57672 |
12 | 1a2b26853497 |
13 | 9cb5b757165 |
14 | 4a93c9b1a95 |
15 | 25c623b41b4 |
hex | 140aed9ebf3 |
1377323052019 has 2 divisors, whose sum is σ = 1377323052020. Its totient is φ = 1377323052018.
The previous prime is 1377323051983. The next prime is 1377323052059. The reversal of 1377323052019 is 9102503237731.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1377323052019 - 219 = 1377322527731 is a prime.
It is a super-2 number, since 2×13773230520192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1377323052059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688661526009 + 688661526010.
It is an arithmetic number, because the mean of its divisors is an integer number (688661526010).
Almost surely, 21377323052019 is an apocalyptic number.
1377323052019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1377323052019 is an equidigital number, since it uses as much as digits as its factorization.
1377323052019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 238140, while the sum is 43.
The spelling of 1377323052019 in words is "one trillion, three hundred seventy-seven billion, three hundred twenty-three million, fifty-two thousand, nineteen".
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