Base | Representation |
---|---|
bin | 1000000001001111111… |
… | …0100011110000111001 |
3 | 111011121201022110101221 |
4 | 2000103332203300321 |
5 | 4224130133314433 |
6 | 143143105312041 |
7 | 12645112461136 |
oct | 2002376436071 |
9 | 434551273357 |
10 | 137774119993 |
11 | 5347a998594 |
12 | 22850335621 |
13 | ccb869ba33 |
14 | 694db7558d |
15 | 38b55e172d |
hex | 2013fa3c39 |
137774119993 has 2 divisors, whose sum is σ = 137774119994. Its totient is φ = 137774119992.
The previous prime is 137774119979. The next prime is 137774120009. The reversal of 137774119993 is 399911477731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92229438249 + 45544681744 = 303693^2 + 213412^2 .
It is a cyclic number.
It is not a de Polignac number, because 137774119993 - 213 = 137774111801 is a prime.
It is not a weakly prime, because it can be changed into another prime (137774119963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68887059996 + 68887059997.
It is an arithmetic number, because the mean of its divisors is an integer number (68887059997).
Almost surely, 2137774119993 is an apocalyptic number.
It is an amenable number.
137774119993 is a deficient number, since it is larger than the sum of its proper divisors (1).
137774119993 is an equidigital number, since it uses as much as digits as its factorization.
137774119993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9001692, while the sum is 61.
The spelling of 137774119993 in words is "one hundred thirty-seven billion, seven hundred seventy-four million, one hundred nineteen thousand, nine hundred ninety-three".
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