1377965420833 has 2 divisors, whose sum is σ = 1377965420834. Its totient is φ = 1377965420832.

The previous prime is 1377965420809. The next prime is 1377965420873. The reversal of 1377965420833 is 3380245697731.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1365738147904 + 12227272929 = 1168648^2 + 110577^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1377965420833 is a prime.

It is a super-2 number, since 2×1377965420833² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1377965420873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688982710416 + 688982710417.

It is an arithmetic number, because the mean of its divisors is an integer number (688982710417).

It is a 2-persistent number, because it is pandigital, and so is 2⋅1377965420833 = 2755930841666, but 3⋅1377965420833 = 4133896262499 is not.

Almost surely, 2^{1377965420833} is an apocalyptic number.

It is an amenable number.

1377965420833 is a deficient number, since it is larger than the sum of its proper divisors (1).

1377965420833 is an equidigital number, since it uses as much as digits as its factorization.

1377965420833 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22861440, while the sum is 58.

The spelling of 1377965420833 in words is "one trillion, three hundred seventy-seven billion, nine hundred sixty-five million, four hundred twenty thousand, eight hundred thirty-three".