Base | Representation |
---|---|
bin | 1100100010000111011011… |
… | …1011011000110000101011 |
3 | 1210210101020100012212012002 |
4 | 3020201312323120300223 |
5 | 3301233423043134341 |
6 | 45150320513441215 |
7 | 2621406310311506 |
oct | 310416673306053 |
9 | 53711210185162 |
10 | 13780250364971 |
11 | 4433198098372 |
12 | 1666855b7020b |
13 | 78c61a0999cc |
14 | 358d7943813d |
15 | 18d6c8bb529b |
hex | c8876ed8c2b |
13780250364971 has 2 divisors, whose sum is σ = 13780250364972. Its totient is φ = 13780250364970.
The previous prime is 13780250364911. The next prime is 13780250364989. The reversal of 13780250364971 is 17946305208731.
13780250364971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13780250364971 - 222 = 13780246170667 is a prime.
It is not a weakly prime, because it can be changed into another prime (13780250364901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6890125182485 + 6890125182486.
It is an arithmetic number, because the mean of its divisors is an integer number (6890125182486).
It is a 1-persistent number, because it is pandigital, but 2⋅13780250364971 = 27560500729942 is not.
Almost surely, 213780250364971 is an apocalyptic number.
13780250364971 is a deficient number, since it is larger than the sum of its proper divisors (1).
13780250364971 is an equidigital number, since it uses as much as digits as its factorization.
13780250364971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7620480, while the sum is 56.
The spelling of 13780250364971 in words is "thirteen trillion, seven hundred eighty billion, two hundred fifty million, three hundred sixty-four thousand, nine hundred seventy-one".
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