Search a number
-
+
13780250364971 is a prime number
BaseRepresentation
bin1100100010000111011011…
…1011011000110000101011
31210210101020100012212012002
43020201312323120300223
53301233423043134341
645150320513441215
72621406310311506
oct310416673306053
953711210185162
1013780250364971
114433198098372
121666855b7020b
1378c61a0999cc
14358d7943813d
1518d6c8bb529b
hexc8876ed8c2b

13780250364971 has 2 divisors, whose sum is σ = 13780250364972. Its totient is φ = 13780250364970.

The previous prime is 13780250364911. The next prime is 13780250364989. The reversal of 13780250364971 is 17946305208731.

13780250364971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13780250364971 - 222 = 13780246170667 is a prime.

It is not a weakly prime, because it can be changed into another prime (13780250364901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6890125182485 + 6890125182486.

It is an arithmetic number, because the mean of its divisors is an integer number (6890125182486).

It is a 1-persistent number, because it is pandigital, but 2⋅13780250364971 = 27560500729942 is not.

Almost surely, 213780250364971 is an apocalyptic number.

13780250364971 is a deficient number, since it is larger than the sum of its proper divisors (1).

13780250364971 is an equidigital number, since it uses as much as digits as its factorization.

13780250364971 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7620480, while the sum is 56.

The spelling of 13780250364971 in words is "thirteen trillion, seven hundred eighty billion, two hundred fifty million, three hundred sixty-four thousand, nine hundred seventy-one".