Base | Representation |
---|---|
bin | 10100000011101001111… |
… | …000111011011010000011 |
3 | 11212202200001002221222101 |
4 | 110003221320323122003 |
5 | 140040241232040233 |
6 | 2533104414451231 |
7 | 201402615602455 |
oct | 24035170733203 |
9 | 4782601087871 |
10 | 1378313549443 |
11 | 4915a307aa86 |
12 | 1a3162503b17 |
13 | 9cc88a17ccc |
14 | 4a9d43682d5 |
15 | 25cbe319c7d |
hex | 140e9e3b683 |
1378313549443 has 2 divisors, whose sum is σ = 1378313549444. Its totient is φ = 1378313549442.
The previous prime is 1378313549399. The next prime is 1378313549453. The reversal of 1378313549443 is 3449453138731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1378313549443 - 217 = 1378313418371 is a prime.
It is a super-2 number, since 2×13783135494432 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1378313549453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 689156774721 + 689156774722.
It is an arithmetic number, because the mean of its divisors is an integer number (689156774722).
Almost surely, 21378313549443 is an apocalyptic number.
1378313549443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1378313549443 is an equidigital number, since it uses as much as digits as its factorization.
1378313549443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13063680, while the sum is 55.
The spelling of 1378313549443 in words is "one trillion, three hundred seventy-eight billion, three hundred thirteen million, five hundred forty-nine thousand, four hundred forty-three".
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