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13784638433 is a prime number
BaseRepresentation
bin11001101011010000…
…01110001111100001
31022120200020012001012
430311220032033201
5211212331412213
610155500350305
7665411331146
oct146550161741
938520205035
1013784638433
115934083975
122808545395
1313b8b067b7
1494aa563cd
1555a2924a8
hex335a0e3e1

13784638433 has 2 divisors, whose sum is σ = 13784638434. Its totient is φ = 13784638432.

The previous prime is 13784638393. The next prime is 13784638471. The reversal of 13784638433 is 33483648731.

13784638433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13779942544 + 4695889 = 117388^2 + 2167^2 .

It is a cyclic number.

It is not a de Polignac number, because 13784638433 - 28 = 13784638177 is a prime.

It is not a weakly prime, because it can be changed into another prime (13784638633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6892319216 + 6892319217.

It is an arithmetic number, because the mean of its divisors is an integer number (6892319217).

Almost surely, 213784638433 is an apocalyptic number.

It is an amenable number.

13784638433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13784638433 is an equidigital number, since it uses as much as digits as its factorization.

13784638433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3483648, while the sum is 50.

The spelling of 13784638433 in words is "thirteen billion, seven hundred eighty-four million, six hundred thirty-eight thousand, four hundred thirty-three".