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1378680594300 = 2232525930118623
BaseRepresentation
bin10100000011111111110…
…001000101111101111100
311212210121121202202212100
4110003333301011331330
5140042014213004200
62533205045505100
7201414663460212
oct24037761057574
94783547682770
101378680594300
11491771287239
121a3245412190
13a0016a8b509
144aa2add0cb2
1525ce166dd00
hex140ffc45f7c

1378680594300 has 216 divisors, whose sum is σ = 4396611098880. Its totient is φ = 361254902400.

The previous prime is 1378680594289. The next prime is 1378680594323. The reversal of 1378680594300 is 34950868731.

1378680594300 is a `hidden beast` number, since 1 + 3 + 7 + 86 + 80 + 59 + 430 + 0 = 666.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 159879789 + ... + 159888411.

Almost surely, 21378680594300 is an apocalyptic number.

1378680594300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1378680594300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2198305549440).

1378680594300 is an abundant number, since it is smaller than the sum of its proper divisors (3017930504580).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1378680594300 is a wasteful number, since it uses less digits than its factorization.

1378680594300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11713 (or 11703 counting only the distinct ones).

The product of its (nonzero) digits is 4354560, while the sum is 54.

The spelling of 1378680594300 in words is "one trillion, three hundred seventy-eight billion, six hundred eighty million, five hundred ninety-four thousand, three hundred".