Base | Representation |
---|---|
bin | 1100100010100111011110… |
… | …0010000001100110100011 |
3 | 1210211012102200202100020222 |
4 | 3020221313202001212203 |
5 | 3301404031202201243 |
6 | 45154302130553255 |
7 | 2622132365533505 |
oct | 310516742014643 |
9 | 53735380670228 |
10 | 13788850428323 |
11 | 4436900657243 |
12 | 166845613882b |
13 | 79038aa2b4a9 |
14 | 3595536a3d75 |
15 | 18da2dbe2168 |
hex | c8a778819a3 |
13788850428323 has 2 divisors, whose sum is σ = 13788850428324. Its totient is φ = 13788850428322.
The previous prime is 13788850428281. The next prime is 13788850428329. The reversal of 13788850428323 is 32382405888731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13788850428323 - 216 = 13788850362787 is a prime.
It is a super-2 number, since 2×137888504283232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13788850428329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6894425214161 + 6894425214162.
It is an arithmetic number, because the mean of its divisors is an integer number (6894425214162).
Almost surely, 213788850428323 is an apocalyptic number.
13788850428323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13788850428323 is an equidigital number, since it uses as much as digits as its factorization.
13788850428323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61931520, while the sum is 62.
The spelling of 13788850428323 in words is "thirteen trillion, seven hundred eighty-eight billion, eight hundred fifty million, four hundred twenty-eight thousand, three hundred twenty-three".
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