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1379203453439 = 7197029064777
BaseRepresentation
bin10100000100011110111…
…011101001000111111111
311212211222001121202202122
4110010132323221013333
5140044102041002224
62533333004313155
7201433642631660
oct24043673510777
94784861552678
101379203453439
11491a0a437029
121a33705427bb
13a009b1b8216
144aa7a617367
1525d2250015e
hex1411eee91ff

1379203453439 has 4 divisors (see below), whose sum is σ = 1576232518224. Its totient is φ = 1182174388656.

The previous prime is 1379203453423. The next prime is 1379203453451. The reversal of 1379203453439 is 9343543029731.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1379203453439 - 24 = 1379203453423 is a prime.

It is a super-3 number, since 3×13792034534393 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1379203453499) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98514532382 + ... + 98514532395.

It is an arithmetic number, because the mean of its divisors is an integer number (394058129556).

Almost surely, 21379203453439 is an apocalyptic number.

1379203453439 is a deficient number, since it is larger than the sum of its proper divisors (197029064785).

1379203453439 is an equidigital number, since it uses as much as digits as its factorization.

1379203453439 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 197029064784.

The product of its (nonzero) digits is 7348320, while the sum is 53.

The spelling of 1379203453439 in words is "one trillion, three hundred seventy-nine billion, two hundred three million, four hundred fifty-three thousand, four hundred thirty-nine".

Divisors: 1 7 197029064777 1379203453439