Base | Representation |
---|---|
bin | 11111010111101110101111… |
… | …011110100011000110110011 |
3 | 200002111211010221221000111222 |
4 | 133113232233132203012303 |
5 | 121041000411142022243 |
6 | 1205234342555055255 |
7 | 41030005432666553 |
oct | 3727565736430663 |
9 | 602454127830458 |
10 | 137970178470323 |
11 | 3aa63907964871 |
12 | 1358366574152b |
13 | 5bca6bba70aa4 |
14 | 260db13dad163 |
15 | 10e3dc33da168 |
hex | 7d7baf7a31b3 |
137970178470323 has 2 divisors, whose sum is σ = 137970178470324. Its totient is φ = 137970178470322.
The previous prime is 137970178470287. The next prime is 137970178470329. The reversal of 137970178470323 is 323074871079731.
It is a strong prime.
It is an emirp because it is prime and its reverse (323074871079731) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 137970178470323 - 212 = 137970178466227 is a prime.
It is not a weakly prime, because it can be changed into another prime (137970178470329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68985089235161 + 68985089235162.
It is an arithmetic number, because the mean of its divisors is an integer number (68985089235162).
Almost surely, 2137970178470323 is an apocalyptic number.
137970178470323 is a deficient number, since it is larger than the sum of its proper divisors (1).
137970178470323 is an equidigital number, since it uses as much as digits as its factorization.
137970178470323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 37340352, while the sum is 62.
The spelling of 137970178470323 in words is "one hundred thirty-seven trillion, nine hundred seventy billion, one hundred seventy-eight million, four hundred seventy thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •