138000680113 has 2 divisors, whose sum is σ = 138000680114. Its totient is φ = 138000680112.

The previous prime is 138000680093. The next prime is 138000680131. The reversal of 138000680113 is 311086000831.

Together with next prime (138000680131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103058976784 + 34941703329 = 321028^2 + 186927^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-138000680113 is a prime.

It is not a weakly prime, because it can be changed into another prime (138000683113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69000340056 + 69000340057.

It is an arithmetic number, because the mean of its divisors is an integer number (69000340057).

Almost surely, 2^138000680113 is an apocalyptic number.

It is an amenable number.

138000680113 is a deficient number, since it is larger than the sum of its proper divisors (1).

138000680113 is an equidigital number, since it uses as much as digits as its factorization.

138000680113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 31.

Adding to 138000680113 its reverse (311086000831), we get a palindrome (449086680944).

The spelling of 138000680113 in words is "one hundred thirty-eight billion, six hundred eighty thousand, one hundred thirteen".