Base | Representation |
---|---|
bin | 101001001000010… |
… | …1101001110000001 |
3 | 10120011220220200212 |
4 | 1102100231032001 |
5 | 10311302024413 |
6 | 344540323505 |
7 | 46125515624 |
oct | 12220551601 |
9 | 3504826625 |
10 | 1380111233 |
11 | 649044aa6 |
12 | 326243595 |
13 | 18cc06b87 |
14 | d1415dbb |
15 | 81266ca8 |
hex | 5242d381 |
1380111233 has 2 divisors, whose sum is σ = 1380111234. Its totient is φ = 1380111232.
The previous prime is 1380111203. The next prime is 1380111241. The reversal of 1380111233 is 3321110831.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1123054144 + 257057089 = 33512^2 + 16033^2 .
It is an emirp because it is prime and its reverse (3321110831) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1380111233 - 212 = 1380107137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1380111199 and 1380111208.
It is not a weakly prime, because it can be changed into another prime (1380111203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690055616 + 690055617.
It is an arithmetic number, because the mean of its divisors is an integer number (690055617).
Almost surely, 21380111233 is an apocalyptic number.
It is an amenable number.
1380111233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1380111233 is an equidigital number, since it uses as much as digits as its factorization.
1380111233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
The square root of 1380111233 is about 37149.8483576986. The cubic root of 1380111233 is about 1113.3661936967.
The spelling of 1380111233 in words is "one billion, three hundred eighty million, one hundred eleven thousand, two hundred thirty-three".
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