Base | Representation |
---|---|
bin | 10100000101011000000… |
… | …011111111011011110011 |
3 | 11212221102212012002122111 |
4 | 110011120003333123303 |
5 | 140103032424141113 |
6 | 2534012044150151 |
7 | 201466461645004 |
oct | 24053003773363 |
9 | 4787385162574 |
10 | 1380161943283 |
11 | 4923614886a2 |
12 | 1a3599538357 |
13 | a01c1950386 |
14 | 4ab2ba3b1ab |
15 | 25d7b73213d |
hex | 141580ff6f3 |
1380161943283 has 2 divisors, whose sum is σ = 1380161943284. Its totient is φ = 1380161943282.
The previous prime is 1380161943191. The next prime is 1380161943287. The reversal of 1380161943283 is 3823491610831.
It is a strong prime.
It is an emirp because it is prime and its reverse (3823491610831) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1380161943283 - 225 = 1380128388851 is a prime.
It is not a weakly prime, because it can be changed into another prime (1380161943287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690080971641 + 690080971642.
It is an arithmetic number, because the mean of its divisors is an integer number (690080971642).
Almost surely, 21380161943283 is an apocalyptic number.
1380161943283 is a deficient number, since it is larger than the sum of its proper divisors (1).
1380161943283 is an equidigital number, since it uses as much as digits as its factorization.
1380161943283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 49.
The spelling of 1380161943283 in words is "one trillion, three hundred eighty billion, one hundred sixty-one million, nine hundred forty-three thousand, two hundred eighty-three".
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