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1380232927393 is a prime number
BaseRepresentation
bin10100000101011100010…
…010110001100010100001
311212221121210202110112121
4110011130102301202201
5140103204112134033
62534023101424241
7201501313210525
oct24053422614241
94787553673477
101380232927393
11492398561051
121a35b926b081
13a0203574ac8
144ab37237d85
1525d82aa462d
hex1415c4b18a1

1380232927393 has 2 divisors, whose sum is σ = 1380232927394. Its totient is φ = 1380232927392.

The previous prime is 1380232927357. The next prime is 1380232927459. The reversal of 1380232927393 is 3937292320831.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1096391185569 + 283841741824 = 1047087^2 + 532768^2 .

It is a cyclic number.

It is not a de Polignac number, because 1380232927393 - 229 = 1379696056481 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1380232927393.

It is not a weakly prime, because it can be changed into another prime (1380232927303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690116463696 + 690116463697.

It is an arithmetic number, because the mean of its divisors is an integer number (690116463697).

Almost surely, 21380232927393 is an apocalyptic number.

It is an amenable number.

1380232927393 is a deficient number, since it is larger than the sum of its proper divisors (1).

1380232927393 is an equidigital number, since it uses as much as digits as its factorization.

1380232927393 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2939328, while the sum is 52.

The spelling of 1380232927393 in words is "one trillion, three hundred eighty billion, two hundred thirty-two million, nine hundred twenty-seven thousand, three hundred ninety-three".