Base | Representation |
---|---|
bin | 10100000101101101101… |
… | …100111011100010100011 |
3 | 11212222101011100010101222 |
4 | 110011231230323202203 |
5 | 140104303344344041 |
6 | 2534112053445255 |
7 | 201511460566664 |
oct | 24055554734243 |
9 | 4788334303358 |
10 | 1380524996771 |
11 | 4925284090a8 |
12 | 1a367b04082b |
13 | a024bc26c1b |
14 | 4ab63d4536b |
15 | 25d9d54874b |
hex | 1416db3b8a3 |
1380524996771 has 2 divisors, whose sum is σ = 1380524996772. Its totient is φ = 1380524996770.
The previous prime is 1380524996759. The next prime is 1380524996789. The reversal of 1380524996771 is 1776994250831.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1380524996771 is a prime.
It is not a weakly prime, because it can be changed into another prime (1380524996371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690262498385 + 690262498386.
It is an arithmetic number, because the mean of its divisors is an integer number (690262498386).
It is a 1-persistent number, because it is pandigital, but 2⋅1380524996771 = 2761049993542 is not.
Almost surely, 21380524996771 is an apocalyptic number.
1380524996771 is a deficient number, since it is larger than the sum of its proper divisors (1).
1380524996771 is an equidigital number, since it uses as much as digits as its factorization.
1380524996771 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22861440, while the sum is 62.
The spelling of 1380524996771 in words is "one trillion, three hundred eighty billion, five hundred twenty-four million, nine hundred ninety-six thousand, seven hundred seventy-one".
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