Base | Representation |
---|---|
bin | 10100000101101110000… |
… | …111111111001111001011 |
3 | 11212222101122200111012212 |
4 | 110011232013333033023 |
5 | 140104312203333203 |
6 | 2534112505455335 |
7 | 201511605101246 |
oct | 24055607771713 |
9 | 4788348614185 |
10 | 1380532089803 |
11 | 492531413209 |
12 | 1a36814a154b |
13 | a025053b599 |
14 | 4ab64c7025d |
15 | 25d9de9a1d8 |
hex | 1416e1ff3cb |
1380532089803 has 2 divisors, whose sum is σ = 1380532089804. Its totient is φ = 1380532089802.
The previous prime is 1380532089763. The next prime is 1380532089917. The reversal of 1380532089803 is 3089802350831.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1380532089803 - 214 = 1380532073419 is a prime.
It is a super-3 number, since 3×13805320898033 (a number of 37 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1380532082803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690266044901 + 690266044902.
It is an arithmetic number, because the mean of its divisors is an integer number (690266044902).
Almost surely, 21380532089803 is an apocalyptic number.
1380532089803 is a deficient number, since it is larger than the sum of its proper divisors (1).
1380532089803 is an equidigital number, since it uses as much as digits as its factorization.
1380532089803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 50.
The spelling of 1380532089803 in words is "one trillion, three hundred eighty billion, five hundred thirty-two million, eighty-nine thousand, eight hundred three".
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