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13806339938 = 248724415807
BaseRepresentation
bin11001101101110110…
…00000011101100010
31022122012001201220122
430312323000131202
5211233410334223
610201553440242
7666063644636
oct146673003542
938565051818
1013806339938
1159453565a6
122813870082
1313c0464521
1494d8a4dc6
1555c12c5c8
hex336ec0762

13806339938 has 16 divisors (see below), whose sum is σ = 20764111104. Its totient is φ = 6884987040.

The previous prime is 13806339871. The next prime is 13806339941. The reversal of 13806339938 is 83993360831.

13806339938 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-4 number, since 4×138063399384 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 13806339938.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2374631 + ... + 2380437.

It is an arithmetic number, because the mean of its divisors is an integer number (1297756944).

Almost surely, 213806339938 is an apocalyptic number.

13806339938 is a deficient number, since it is larger than the sum of its proper divisors (6957771166).

13806339938 is a wasteful number, since it uses less digits than its factorization.

13806339938 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8737.

The product of its (nonzero) digits is 2519424, while the sum is 53.

The spelling of 13806339938 in words is "thirteen billion, eight hundred six million, three hundred thirty-nine thousand, nine hundred thirty-eight".

Divisors: 1 2 487 974 2441 4882 5807 11614 1188767 2377534 2828009 5656018 14174887 28349774 6903169969 13806339938