Base | Representation |
---|---|
bin | 1100100011101001000100… |
… | …0000001011110101000010 |
3 | 1210212212212202211001220222 |
4 | 3020322101000023311002 |
5 | 3302201111123242424 |
6 | 45210333222303042 |
7 | 2623324614365135 |
oct | 310722100136502 |
9 | 53785782731828 |
10 | 13806457634114 |
11 | 4443316445592 |
12 | 166b94a887a82 |
13 | 791c35771262 |
14 | 35a343c8421c |
15 | 18e20e85be5e |
hex | c8e9100bd42 |
13806457634114 has 4 divisors (see below), whose sum is σ = 20709686451174. Its totient is φ = 6903228817056.
The previous prime is 13806457634071. The next prime is 13806457634141. The reversal of 13806457634114 is 41143675460831.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8466453020089 + 5340004614025 = 2909717^2 + 2310845^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3451614408527 + ... + 3451614408530.
Almost surely, 213806457634114 is an apocalyptic number.
13806457634114 is a deficient number, since it is larger than the sum of its proper divisors (6903228817060).
13806457634114 is an equidigital number, since it uses as much as digits as its factorization.
13806457634114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6903228817059.
The product of its (nonzero) digits is 5806080, while the sum is 53.
The spelling of 13806457634114 in words is "thirteen trillion, eight hundred six billion, four hundred fifty-seven million, six hundred thirty-four thousand, one hundred fourteen".
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