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1381211497 is a prime number
BaseRepresentation
bin101001001010011…
…1001110101101001
310120020222210222101
41102110321311221
510312042231442
6345020053401
746141050451
oct12224716551
93506883871
101381211497
11649726706
12326694261
13190200913
14d1620d61
15813d2cb7
hex52539d69

1381211497 has 2 divisors, whose sum is σ = 1381211498. Its totient is φ = 1381211496.

The previous prime is 1381211483. The next prime is 1381211509. The reversal of 1381211497 is 7941121831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1369814121 + 11397376 = 37011^2 + 3376^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1381211497 is a prime.

It is not a weakly prime, because it can be changed into another prime (1381211407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690605748 + 690605749.

It is an arithmetic number, because the mean of its divisors is an integer number (690605749).

Almost surely, 21381211497 is an apocalyptic number.

It is an amenable number.

1381211497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1381211497 is an equidigital number, since it uses as much as digits as its factorization.

1381211497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12096, while the sum is 37.

The square root of 1381211497 is about 37164.6538662746. The cubic root of 1381211497 is about 1113.6619841910.

It can be divided in two parts, 1381 and 211497, that added together give a triangular number (212878 = T652).

The spelling of 1381211497 in words is "one billion, three hundred eighty-one million, two hundred eleven thousand, four hundred ninety-seven".