Base | Representation |
---|---|
bin | 1000000011001111110… |
… | …1100101010000100011 |
3 | 111020000010001022122111 |
4 | 2000303331211100203 |
5 | 4231230022004013 |
6 | 143312235020151 |
7 | 12664316564056 |
oct | 2006375452043 |
9 | 436003038574 |
10 | 138310734883 |
11 | 53725893272 |
12 | 2297bb9a657 |
13 | 10072903939 |
14 | 69a113ca9d |
15 | 38e778d73d |
hex | 2033f65423 |
138310734883 has 2 divisors, whose sum is σ = 138310734884. Its totient is φ = 138310734882.
The previous prime is 138310734869. The next prime is 138310734893. The reversal of 138310734883 is 388437013831.
It is a strong prime.
It is an emirp because it is prime and its reverse (388437013831) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 138310734883 - 25 = 138310734851 is a prime.
It is not a weakly prime, because it can be changed into another prime (138310734803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69155367441 + 69155367442.
It is an arithmetic number, because the mean of its divisors is an integer number (69155367442).
Almost surely, 2138310734883 is an apocalyptic number.
138310734883 is a deficient number, since it is larger than the sum of its proper divisors (1).
138310734883 is an equidigital number, since it uses as much as digits as its factorization.
138310734883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1161216, while the sum is 49.
The spelling of 138310734883 in words is "one hundred thirty-eight billion, three hundred ten million, seven hundred thirty-four thousand, eight hundred eighty-three".
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