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138320494993 is a prime number
BaseRepresentation
bin1000000011010010001…
…0110100000110010001
3111020000210102012000001
42000310202310012101
54231240021314433
6143313224130001
712664465544152
oct2006442640621
9436023365001
10138320494993
115373034a17a
1222983306901
1310074940255
1469a255d929
1538e856a57d
hex20348b4191

138320494993 has 2 divisors, whose sum is σ = 138320494994. Its totient is φ = 138320494992.

The previous prime is 138320494967. The next prime is 138320495017. The reversal of 138320494993 is 399494023831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113699119249 + 24621375744 = 337193^2 + 156912^2 .

It is a cyclic number.

It is not a de Polignac number, because 138320494993 - 229 = 137783624081 is a prime.

It is not a weakly prime, because it can be changed into another prime (138320494093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69160247496 + 69160247497.

It is an arithmetic number, because the mean of its divisors is an integer number (69160247497).

Almost surely, 2138320494993 is an apocalyptic number.

It is an amenable number.

138320494993 is a deficient number, since it is larger than the sum of its proper divisors (1).

138320494993 is an equidigital number, since it uses as much as digits as its factorization.

138320494993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5038848, while the sum is 55.

The spelling of 138320494993 in words is "one hundred thirty-eight billion, three hundred twenty million, four hundred ninety-four thousand, nine hundred ninety-three".