Base | Representation |
---|---|
bin | 11111011100111000111110… |
… | …100110001100010000001001 |
3 | 200010202201101211200022210000 |
4 | 133130320332212030100021 |
5 | 121112303110313342100 |
6 | 1210105304244313213 |
7 | 41064430450132200 |
oct | 3734707646142011 |
9 | 603681354608700 |
10 | 138324766934025 |
11 | 400902278a6881 |
12 | 136203246a2809 |
13 | 5c24c7b14a799 |
14 | 2622d50db8237 |
15 | 10ed2281a3900 |
hex | 7dce3e98c409 |
138324766934025 has 135 divisors (see below), whose sum is σ = 298065966938949. Its totient is φ = 63232485563520.
The previous prime is 138324766933967. The next prime is 138324766934033. The reversal of 138324766934025 is 520439667423831.
The square root of 138324766934025 is 11761155.
It is a perfect power (a square), and thus also a powerful number.
138324766934025 is a `hidden beast` number, since 1 + 3 + 8 + 32 + 476 + 6 + 93 + 40 + 2 + 5 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 72603841401 + 138252163092624 = 269451^2 + 11758068^2 .
It is a tau number, because it is divible by the number of its divisors (135).
It is not a de Polignac number, because 138324766934025 - 215 = 138324766901257 is a prime.
It is a super-2 number, since 2×1383247669340252 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is an unprimeable number.
It is a polite number, since it can be written in 134 ways as a sum of consecutive naturals, for example, 3704745157 + ... + 3704782493.
It is a 1-persistent number, because it is pandigital, but 2⋅138324766934025 = 276649533868050 is not.
Almost surely, 2138324766934025 is an apocalyptic number.
138324766934025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
138324766934025 is the 11761155-th square number.
138324766934025 is the 5880578-th centered octagonal number.
It is an amenable number.
138324766934025 is an abundant number, since it is smaller than the sum of its proper divisors (159741200004924).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
138324766934025 is an frugal number, since it uses more digits than its factorization.
138324766934025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74710 (or 37352 counting only the distinct ones).
The product of its (nonzero) digits is 156764160, while the sum is 63.
The spelling of 138324766934025 in words is "one hundred thirty-eight trillion, three hundred twenty-four billion, seven hundred sixty-six million, nine hundred thirty-four thousand, twenty-five".
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