Base | Representation |
---|---|
bin | 1000000011011001100… |
… | …1100010000010010011 |
3 | 111020002221222022012101 |
4 | 2000312121202002103 |
5 | 4231321003204042 |
6 | 143320255141231 |
7 | 12665324222323 |
oct | 2006631420223 |
9 | 436087868171 |
10 | 138351616147 |
11 | 53746975a38 |
12 | 22991814817 |
13 | 1007b218634 |
14 | 69a6741283 |
15 | 38eb1666b7 |
hex | 2036662093 |
138351616147 has 2 divisors, whose sum is σ = 138351616148. Its totient is φ = 138351616146.
The previous prime is 138351616063. The next prime is 138351616177. The reversal of 138351616147 is 741616153831.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 138351616147 - 219 = 138351091859 is a prime.
It is a super-2 number, since 2×1383516161472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 138351616097 and 138351616106.
It is not a weakly prime, because it can be changed into another prime (138351616177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69175808073 + 69175808074.
It is an arithmetic number, because the mean of its divisors is an integer number (69175808074).
Almost surely, 2138351616147 is an apocalyptic number.
138351616147 is a deficient number, since it is larger than the sum of its proper divisors (1).
138351616147 is an equidigital number, since it uses as much as digits as its factorization.
138351616147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 362880, while the sum is 46.
Adding to 138351616147 its reverse (741616153831), we get a palindrome (879967769978).
The spelling of 138351616147 in words is "one hundred thirty-eight billion, three hundred fifty-one million, six hundred sixteen thousand, one hundred forty-seven".
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