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13840211483 = 77392675471
BaseRepresentation
bin11001110001111000…
…01101111000011011
31022201112210120221022
430320330031320123
5211321043231413
610205203433055
7666654566540
oct147074157033
938645716838
1013840211483
11596249080a
12282308578b
1313c7493767
149541a0bc7
155600bd608
hex338f0de1b

13840211483 has 8 divisors (see below), whose sum is σ = 15838794240. Its totient is φ = 11846981160.

The previous prime is 13840211471. The next prime is 13840211531. The reversal of 13840211483 is 38411204831.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13840211483 - 26 = 13840211419 is a prime.

It is a super-3 number, since 3×138402114833 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13840211783) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1332563 + ... + 1342908.

It is an arithmetic number, because the mean of its divisors is an integer number (1979849280).

Almost surely, 213840211483 is an apocalyptic number.

13840211483 is a deficient number, since it is larger than the sum of its proper divisors (1998582757).

13840211483 is an equidigital number, since it uses as much as digits as its factorization.

13840211483 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2676217.

The product of its (nonzero) digits is 18432, while the sum is 35.

The spelling of 13840211483 in words is "thirteen billion, eight hundred forty million, two hundred eleven thousand, four hundred eighty-three".

Divisors: 1 7 739 5173 2675471 18728297 1977173069 13840211483