Base | Representation |
---|---|
bin | 11001110001111000… |
… | …01101111000001111 |
3 | 1022201112210120220212 |
4 | 30320330031320033 |
5 | 211321043231341 |
6 | 10205203433035 |
7 | 666654566522 |
oct | 147074157017 |
9 | 38645716825 |
10 | 13840211471 |
11 | 59624907a9 |
12 | 282308577b |
13 | 13c7493758 |
14 | 9541a0bb9 |
15 | 5600bd5eb |
hex | 338f0de0f |
13840211471 has 2 divisors, whose sum is σ = 13840211472. Its totient is φ = 13840211470.
The previous prime is 13840211419. The next prime is 13840211531. The reversal of 13840211471 is 17411204831.
It is a weak prime.
It is an emirp because it is prime and its reverse (17411204831) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13840211471 - 230 = 12766469647 is a prime.
It is a super-3 number, since 3×138402114713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13840211771) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6920105735 + 6920105736.
It is an arithmetic number, because the mean of its divisors is an integer number (6920105736).
Almost surely, 213840211471 is an apocalyptic number.
13840211471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13840211471 is an equidigital number, since it uses as much as digits as its factorization.
13840211471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 32.
The spelling of 13840211471 in words is "thirteen billion, eight hundred forty million, two hundred eleven thousand, four hundred seventy-one".
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