13840211531 has 2 divisors, whose sum is σ = 13840211532. Its totient is φ = 13840211530.

The previous prime is 13840211471. The next prime is 13840211569. The reversal of 13840211531 is 13511204831.

It is a strong prime.

It is an emirp because it is prime and its reverse (13511204831) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13840211531 is a prime.

It is a super-3 number, since 3×13840211531³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13840211494 and 13840211503.

It is not a weakly prime, because it can be changed into another prime (13840111531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6920105765 + 6920105766.

It is an arithmetic number, because the mean of its divisors is an integer number (6920105766).

Almost surely, 2^13840211531 is an apocalyptic number.

13840211531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13840211531 is an equidigital number, since it uses as much as digits as its factorization.

13840211531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 29.

The spelling of 13840211531 in words is "thirteen billion, eight hundred forty million, two hundred eleven thousand, five hundred thirty-one".