Base | Representation |
---|---|
bin | 11001110010001001… |
… | …10011101110100011 |
3 | 1022201201001000022221 |
4 | 30321010303232203 |
5 | 211322132314101 |
6 | 10205324011511 |
7 | 1000012666612 |
oct | 147104635643 |
9 | 38651030287 |
10 | 13842463651 |
11 | 5963789905 |
12 | 2823990b97 |
13 | 13c7aa18c3 |
14 | 9545c9879 |
15 | 5603b5aa1 |
hex | 339133ba3 |
13842463651 has 2 divisors, whose sum is σ = 13842463652. Its totient is φ = 13842463650.
The previous prime is 13842463561. The next prime is 13842463721. The reversal of 13842463651 is 15636424831.
Together with previous prime (13842463561) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13842463651 - 217 = 13842332579 is a prime.
It is a super-2 number, since 2×138424636512 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13842463598 and 13842463607.
It is not a weakly prime, because it can be changed into another prime (13842463351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6921231825 + 6921231826.
It is an arithmetic number, because the mean of its divisors is an integer number (6921231826).
Almost surely, 213842463651 is an apocalyptic number.
13842463651 is a deficient number, since it is larger than the sum of its proper divisors (1).
13842463651 is an equidigital number, since it uses as much as digits as its factorization.
13842463651 is an evil number, because the sum of its binary digits is even.
The product of its digits is 414720, while the sum is 43.
The spelling of 13842463651 in words is "thirteen billion, eight hundred forty-two million, four hundred sixty-three thousand, six hundred fifty-one".
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