Base | Representation |
---|---|
bin | 11001110010101100… |
… | …01101000011100011 |
3 | 1022202000121200201221 |
4 | 30321112031003203 |
5 | 211324314230333 |
6 | 10210005435511 |
7 | 1000066521622 |
oct | 147126150343 |
9 | 38660550657 |
10 | 13847023843 |
11 | 5966313a64 |
12 | 282540bb97 |
13 | 13c8a0a443 |
14 | 9550556b9 |
15 | 5609b6d2d |
hex | 33958d0e3 |
13847023843 has 2 divisors, whose sum is σ = 13847023844. Its totient is φ = 13847023842.
The previous prime is 13847023829. The next prime is 13847023943. The reversal of 13847023843 is 34832074831.
13847023843 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13847023843 - 217 = 13846892771 is a prime.
It is a super-2 number, since 2×138470238432 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13847023843.
It is not a weakly prime, because it can be changed into another prime (13847023643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6923511921 + 6923511922.
It is an arithmetic number, because the mean of its divisors is an integer number (6923511922).
Almost surely, 213847023843 is an apocalyptic number.
13847023843 is a deficient number, since it is larger than the sum of its proper divisors (1).
13847023843 is an equidigital number, since it uses as much as digits as its factorization.
13847023843 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 387072, while the sum is 43.
The spelling of 13847023843 in words is "thirteen billion, eight hundred forty-seven million, twenty-three thousand, eight hundred forty-three".
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