138506927243 has 2 divisors, whose sum is σ = 138506927244. Its totient is φ = 138506927242.

The previous prime is 138506927227. The next prime is 138506927249. The reversal of 138506927243 is 342729605831.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 138506927243 - 2⁴ = 138506927227 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 138506927191 and 138506927200.

It is not a weakly prime, because it can be changed into another prime (138506927249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69253463621 + 69253463622.

It is an arithmetic number, because the mean of its divisors is an integer number (69253463622).

It is a 1-persistent number, because it is pandigital, but 2⋅138506927243 = 277013854486 is not.

Almost surely, 2^138506927243 is an apocalyptic number.

138506927243 is a deficient number, since it is larger than the sum of its proper divisors (1).

138506927243 is an equidigital number, since it uses as much as digits as its factorization.

138506927243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 50.

The spelling of 138506927243 in words is "one hundred thirty-eight billion, five hundred six million, nine hundred twenty-seven thousand, two hundred forty-three".